First, we need to convert the power ratings to amps using Ohm's law:
I = P / V
For the heating load:
I_heat = 8000W / 240V = 33.33 amps
For the cooling load:
I_cool = 7000W / 240V = 29.17 amps
Since both loads will operate simultaneously, we need to add the current values to find the total current draw:
I_total = I_heat + I_cool = 33.33 amps + 29.17 amps = 62.5 amps
Now, we need to choose a circuit breaker that is rated for a continuous load that is equal to or greater than the total current draw. Based on the calculated current of 62.5 amps, the closest standard breaker size is 70 amps.
Therefore, a 70-amp circuit breaker would be appropriate for this application.
