$$V = \pi r^2 h$$
Where:
* V is the volume of the cylinder in cubic millimeters (mm³)
* r is the radius of the cylinder in millimeters (mm)
* h is the height of the cylinder in millimeters (mm)
In this case, the bore of the piston is 62mm, which means the radius (r) is half of that, or 31mm. The stroke of the piston is 42.18mm, which is the height (h) of the cylinder.
So, plugging these values into the formula, we get:
$$V = \pi (31^2) (42.18)$$
$$V = \pi (961) (42.18)$$
$$V \approx 128,965 mm³$$
Therefore, the volume of the piston is approximately 128,965 cubic millimeters.
