Generator speed (N₁) = 1000 rpm
Output voltage (V₁) = 140 volts
Output current (I₁) = 8.5 amps
New speed (N₂) = 3000 rpm
To find:
Power taken by the cooling blower (P₂)
Formula:
$$P_2 = P_1 \times \frac{N_2}{N_1}$$
where P₁ is the power taken by the cooling blower at speed N₁.
First, we need to find the power (P₁) taken by the cooling blower at 1000 rpm.
$$P_1 = V_1 \times I_1$$
Substituting the given values:
$$P_1 = 140 \times 8.5 = 1190 \text{ watts}$$
Now, we can calculate P₂ using the formula:
$$P_2 = 1190 \times \frac{3000}{1000}$$
$$P_2 = 3570 \text{ watts}$$
Therefore, the power taken by the cooling blower at 3000 rpm is 3570 watts.
