The first car gets an avergae of 25 miles per gallon while the second 15 two cars combined drive a total 1100 in that week consuming 60 gallons gas how many?

Let's represent the distance traveled by the first car as x miles and the distance traveled by the second car as y miles. We know that the total distance traveled by both cars is 1100 miles, so we can write:

```

x + y = 1100

```

We also know that the first car gets an average of 25 miles per gallon, so the amount of gas it consumes can be calculated as:

```

gas1 = x / 25

```

Similarly, the amount of gas consumed by the second car can be calculated as:

```

gas2 = y / 15

```

The total amount of gas consumed by both cars is given as 60 gallons, so we can write:

```

gas1 + gas2 = 60

```

Substituting the expressions for gas1 and gas2, we get:

```

x / 25 + y / 15 = 60

```

Multiplying both sides by 75 (the least common multiple of 25 and 15), we get:

```

3x + 5y = 4500

```

Now we have a system of two linear equations:

```

x + y = 1100

3x + 5y = 4500

```

We can solve this system using elimination or substitution method. Let's use the elimination method:

```

(-3) * (x + y) = (-3) * 1100

3x + 5y = 4500

-3x - 3y = -3300

3x + 5y = 4500

```

Adding these two equations, we get:

```

2y = 1200

```

Dividing both sides by 2, we get:

```

y = 600

```

Now we can substitute this value of y back into the first equation:

```

x + y = 1100

x + 600 = 1100

```

Subtracting 600 from both sides, we get:

```

x = 500

```

Therefore, the first car traveled 500 miles and the second car traveled 600 miles.