What is the amps of a 9v battery?

The current (in amperes) that a 9V battery can deliver depends on the battery's capacity and internal resistance. A typical 9V battery has a capacity of around 500-600 mAh (milliamp-hours). This means that it can deliver a current of 500-600 mA for one hour, or a lower current for a longer period of time.

The internal resistance of a 9V battery is typically around 0.5-1 ohm. This means that the battery will lose some voltage when it is delivering a current. For example, if a 9V battery is delivering a current of 100 mA, the voltage at the battery terminals will be around 8.9V.

To calculate the maximum current that a 9V battery can deliver, you can use the following formula:

```

I = V / R

```

where:

* I is the current in amperes (A)

* V is the voltage in volts (V)

* R is the internal resistance in ohms (Ω)

For example, if a 9V battery has an internal resistance of 0.5 ohms, the maximum current that it can deliver is:

```

I = 9V / 0.5Ω = 18A

```

However, it is important to note that this is the maximum current that the battery can deliver for a very short period of time. In practice, the battery will not be able to deliver this current for very long because the voltage will drop too low.

A more realistic value for the maximum current that a 9V battery can deliver is around 1-2A. This is enough current to power most small electronic devices, such as radios, calculators, and toys.